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输入年份,判断是否为闰年 #include <stdio.h> int main(void) { int year; int is_leap_year(int year); printf("Enter a year :\n"); scanf("%d",&year); is_leap_year(year); return 0; } int is_leap_year(int year) { if (!(year%4)) { if(year%100) printf("%d is a leap year\n",year); else if(!(year%400)) printf("%d is a leap year\n",year); else printf("%d is not a leap year\n",year); } else printf("%d is not a leap year\n",year); return 0; }
#include <stdio.h> void is_leap_year(int year) { if((year%4 == 0 && year%100 != 0) || year%400 == 0) { printf("%d 是闰年\n",year); return; } else printf("%d 不是闰年",year); return; } int main(void) { int year; printf("Enter a year :\n"); scanf("%d",&year); is_leap_year(year); return; }
#include <math.h> #include <stdio.h> double myround(double num) { double numx = num-floor(num); double numy = ceil(num)-num; if(numx > numy) { printf("值为: %.2f", ceil(num)); }else{ printf("值为: %.2f", floor(num)); } } main(void) { double y=2.55; myround(y); }
下面这两个答案对吗? 1. #include<stdio.h> int is_leap_year(int year) { if((year%4==0&&year%100!=0)||year%400==0) printf("%d is leap year.\n",year); else printf("%d is not leap year.\n",year); return 0; } int main(void) { int n; printf("Enter a year:"); scanf("%d",&n); is_leap_year(n); return 0; } 2. #include <math.h> #include <stdio.h> double myround(double num) { double numx = num-floor(num); double numy = ceil(num)-num; if((numx >= numy&&num>0)||!(numx<=numy&&num<0)) { printf("rounding:%.1f\n", ceil(num)); return 0; }else{ printf("rounding:%.1f\n", floor(num)); return 0; } } int main(void) { double n; scanf("%lf",&n); myround(n); return 0; }
#include<stdio.h> int is_leap_year(int year){ if(year%4==0 && year%100!=0 || year%400==0) printf("The year is leap year\n"); else printf("The year isn't leap year\n"); } int main(void){ is_leap_year(2008); is_leap_year(2009); }
第一位同学做的对吗?
2. #include <stdio.h> #include <math.h> double myround(double x) { return floor(x+0.5); } int main(void) { printf("myround(4.49) = %f\n", myround(4.49)); printf("myround(4.59) = %f\n", myround(4.59)); printf("myround(-3.51) = %f\n", myround(-3.51)); printf("myround(-3.41) = %f\n", myround(-3.41)); return 0; } 提供一种方法,感觉不如sunlick的数学性好
1. #include <stdio.h> int is_leap_year(int year) { return ( (!(year%4)&&(year%100)) || !(year%400) ); } int main(void) { printf("is_leap_year(2000) = %d\n", is_leap_year(2000)); printf("is_leap_year(2001) = %d\n", is_leap_year(2001)); printf("is_leap_year(2002) = %d\n", is_leap_year(2002)); printf("is_leap_year(2003) = %d\n", is_leap_year(2003)); printf("is_leap_year(2004) = %d\n", is_leap_year(2004)); printf("is_leap_year(2009) = %d\n", is_leap_year(2009)); printf("is_leap_year(1900) = %d\n", is_leap_year(1900)); return 0; } 写程序就像说话一样,那个爽!
#include <stdio.h> double myround(double x){ if (x > 0) { return (int)(x + 0.5); }else{ return (int)(x - 0.5); } } int main(void) { double a = myround(-3.51); double b = myround(4.49); printf("%f %f\n", a, b); }
第一位同学好像2000年是个闰年吧?你的算法能出这个?
int is_leap_year(int year){ if(year%100!=0&&year%4==0) return 1; if(year%400==0) return 1; return 0; }
answer 1: int is_leap_year(int year) { if (year % 4 == 0 && year % 100 != 0 ) return 1; elseif (year % 400 = 0) return 1; else return 0; }
myround(-3.51)的值是-4.0 这个不5入么 入不是变大么?咋就变小了呢?
#include <stdio.h> #include <math.h> double myround(double num); void main() { double num; printf("input a num:"); scanf("%lf",&num); printf("%lf\n",myround(num)); } double myround(double num) { if(num>=0) { return floor(num+0.5); } else return ceil(num-0.5); }
想了个自以为比较简洁的方法: #include <stdio.h> #include <math.h> double myround(double x) { int temp; if ((temp = ceil(x)) - x <= 0.5) return temp; else return floor(x); } int main(void) { printf("%f\n", myround(3.5)); return 0; }
#include <stdio.h> #include <math.h> double myround(double num); main(void) { double a = 2.55; myround(a); } double myround(double num) { double num1 = num-floor(num); double num2 = ceil(num) - num; if(num1 > num2 ) { printf("%f\n",ceil(num)); } else{ printf("%f\n", floor(num)); } } 编译的时候出现了以下的错误: /tmp/ccYC5s8n.o: In function `main': night.c:(.text+0x1b): undefined reference to `ceil' collect2: ld returned 1 exit status panabit@panabit-desk:~/cprogress$ vim eight.C panabit@panabit-desk:~/cprogress$ vim seven.c panabit@panabit-desk:~/cprogress$ vim six.c panabit@panabit-desk:~/cprogress$ gcc six.c /tmp/ccKpuCMl.o: In function `myround': six.c:(.text+0x3c): undefined reference to `floor' six.c:(.text+0x4f): undefined reference to `ceil' six.c:(.text+0x74): undefined reference to `ceil' six.c:(.text+0x92): undefined reference to `floor' collect2: ld returned 1 exit status
没有加-lm
#include <math.h> #include <stdio.h> /* int is_leap_year(int year) { return (year%4==0 && year%100!=0) || year%400==0; } int main(void) { int i=1; while(i<=2010) { if(is_leap_year(i)) printf("%d ",i); i=i+1; } printf("\n"); return 0; } */ double myround(double x) { if(ceil(x)-x<x-floor(x)) return ceil(x); else if((ceil(x)-x==x-floor(x)) && x>0) return ceil(x); else if((ceil(x)-x==x-floor(x)) && x<=0) return floor(x); else return floor(x); } int main(void) { double x; printf("input a number:"); scanf("%lf",&x); printf("四舍五入之后:%lf\n",myround(x)); return 0; }
#include<stdio.h> #include<math.h> int main(void) { double x; double myround( double x); printf("这个一个求四舍五入的程序,请输入:"); scanf("%lf",&x); myround(x); return 0; } double myround(double x) { double y=x+0.5; if ( x >0) { if (y < ceil(x)) { printf("四舍:%f\n",floor(x)); } else {printf("五入:%f\n",ceil(x)); } } else { if (y > ceil(x)) { printf("四舍:%f\n",ceil(x)); else {printf("五入:%f\n",floor(x)); } } return 0; } 第二道题目
看了楼上的答案,第二题那么多解法中,貌似只有4位同学是对的,其中9楼 tianyebj 同学和14楼 zdx1314 同学的解法最简洁, tianyebj: ------------------代码分割线----------------- double myround(double x) { if (x > 0) return (int)(x + 0.5); else return (int)(x - 0.5); } ------------------代码分割线----------------- zdx1314: ------------------代码分割线----------------- double myround(double num) { if(num>=0) return floor(num+0.5); else return ceil(num-0.5); } ------------------代码分割线----------------- 这两种方法其实一样,因为double强制转换为int是向0截断,即正数取floor负数取ceil。 另外楼上 asdf & mm 也是正确的,其他我看着好像都有错,用1.5,-1.5测试一下即知。
多谢LS提醒,我加了个fabs: #include <stdio.h> #include <math.h> double myround(double x) { int temp; if (fabs((temp = ceil(x))) - x <= 0.5) return temp; else return floor(x); } int main(void) { printf("%f\n", myround(1.5)); return 0; }
觉得sunlick xxx@gmail.com 做的有些问题啊。当传的参数值正好是2.5或者-2.5之类的值时,是不对的。
#include <stdio.h> int is_leap_year(int x) { return ((x%4==0 && x%100!=0)||(x%400==0)); } int main(void) { int a; printf("Please input year number:\n"); scanf("%d",&a); if (is_leap_year(a)){printf("This is leap year!\n");} else {printf("This is common year!\n");} system("pause"); }
//1 #include <stdio.h> int is_leap_year(int year) { if(((year % 4 == 0)&&(year % 100 != 0))||(year % 400 == 0)) return 1; else return 0; } int main(void) { int i, year; for(i = 0; ; i++) { scanf("%d", &year); if(is_leap_year(year)) printf("%d is a leap year.\n", year); else printf("%d is not a leap year.\n", year); if(year == 9999) break; } return 0; } //2 #include <stdio.h> #include <math.h> double myround(double x) { return floor(x); } int main(void) { int i; double x; scanf("%lf", &x); printf("myround of %lf is %lf.\n", x, myround(x)); return 0; }
laciqs 530107999@qq.com 2010-08-02 12:37:54 多谢LS提醒,我加了个fabs: #include <stdio.h> #include <math.h> double myround(double x) { int temp; if (fabs((temp = ceil(x))) - x <= 0.5) return temp; else return floor(x); } int main(void) { printf("%f\n", myround(1.5)); return 0; } 这个哥们的程序用有问题。用-2.6试试。你会返回-2而不是-3。
# include "stdafx.h" int is_leap_year(int year) { if(0 == year % 4 && 0 != year % 100 || 0 == year % 400) { return 1; } else { return 0; } } int main(void) { int year = 1999, result = 3; printf("Please input how is year\n"); scanf("%d", &year); result = is_leap_year(year); if(1 == result) { printf("This year is leap year!\n"); } else { printf("This year is not leap year!\n"); } return 0; }
# include <stdio.h> # include <math.h> double myround(double x) { if(x > 0) { if(fabs(ceil(x) - x) <= 0.5) { //printf("ceil(x) - x = %lf\n", ceil(x) - x); //printf("fabs(ceil(x) - x) = %lf\n", fabs(ceil(x) - x)); return ceil(x); } else { //printf("ceil(x) - x = %lf\n", ceil(x) - x); //printf("fabs(ceil(x) - x) = %lf\n", fabs(ceil(x) - x)); return floor(x); } } else { if(fabs(floor(x) - x) <= 0.5) { //printf("floor(x) - x = %lf\n", floor(x) - x); //printf("fabs(floor(x) - x) = %lf\n", fabs(floor(x) - x)); return floor(x); } else { //printf("floor(x) - x = %lf\n", floor(x) - x); //printf("fabs(floor(x) - x) = %lf\n", fabs(floor(x) - x)); return ceil(x); } } } int main(void) { double x = 0, result = 0; printf("Please input no zero number!\n"); scanf("%lf", &x); if(0 == x) { printf("Please input no zero number!\n"); scanf("%lf", &x); while(0 == x) { printf("Please input no zero number!\n"); scanf("%lf", &x); } } else { result = myround(x); } printf("The number after round is %lf\n", result); return 0; }
#include<stdio.h> #include<math.h> int main(void) { double myround(double); float i; printf("Please input a double_num: "); scanf("%f",&i); myround(i); return 0; } double myround(double num) { int x; if(num>0) { x=(num*10); if(x%10>=5) { printf("%.1f",ceil(num)); return 0; } else { printf("%.1f",floor(num)); return 0; } } else { x=-num*10; if(x%10>=5) { printf("%.1f",floor(num)); return 0; } else { printf("%.1f",ceil(num)); return 0; } } } else { printf("%.1f",floor(num)); return 0; } } else { x=-num*10; if(x%10>=5) { printf("%.1f",floor(num)); return 0; } else { printf("%.1f",ceil(num)); return 0; } } }
对不起,最后21行贴重复了,不能重新编辑。。。
1 #include<stdio.h> 2 #include<math.h> 3 double myround(double x) 4 { if(x>=0){ 5 if((x-floor(x)) >= 0.5) { 6 7 printf("you enter number is %.2lf,reson:%.2f",x,ceil(x)); 8 9 return 0; 10 11 }else{ 12 13 printf("you enter number %.2lf,reson is:%.2f",x,floor(x)); 14 15 return 0; 16 }}else{ 17 if ((ceil(x)-x) >= 0.5) { 18 19 printf ("%lf",floor(x)); 20 21 return 0; 22 }else{ 23 24 printf("%lf",ceil(x)); 25 return 0; 26 } 27 } 28 } 29 30 int main(void) 31 { 32 double z; 33 printf("Please enter a number with two decimal places: "); 34 scanf("%lf",&z); 35 myround(z); 36 return 0; 37 } 不知道有没有更简单的方法。
/* First Question */ #include <stdio.h> int is_leap_year(int year) { if(year%400==0) { printf("%d is a leap year.\n", year) ; } else { if(year%4==0&&year%100!=0) { printf("%d is a leap year\n.", year) ; } else { printf("%d is NOT a leap year\n.", year) ; } } return 0 ; } int main(void) { int year ; int i ; printf("Please input the year: It should be less than 10000 and more than 0.\n") ; printf("Year="); i = scanf("%d", &year) ; if(i == 1) { if(year<1||year>9999) { printf("It is NOt a correct input!\n") ; } else { is_leap_year(year) ; } } else { printf("It is NOt a correct input!\n") ; } return 0 ; }
/* Second Question */ #include <stdio.h> #include <math.h> int myround(double i) { int k = (int)i ; //printf("%d\n", k) ; if(i>=0.0) { if(i-k<0.5&&i-k>-0.5) { k = floor(i) ; //printf("A\n") ; } else { k = ceil(i) ; //printf("B\n") ; } } else { if(i-k<0.5&&i-k>-0.5) { k = ceil(i) ; //printf("C\n") ; } else { k = floor(i) ; //printf("D\n") ; } } printf("Number=%d\n", k) ; return 0 ; } int main(void) { double i ; int j ; printf("Please input a number.\n") ; printf("Number=") ; j = scanf("%lf", &i) ; if(j == 1) { myround(i) ; } else { printf("It is NOt a correct input!\n") ; } return 0 ; }
1 #include<stdio.h> 2 #include<stdlib.h> 3 4 int is_leap_year(int year); 5 int main(int argc, char * argv[]) 6 { 7 8 int leap_flag,year; 9 printf("in put your year:>>>>>>\n"); 10 scanf("%d",&year); 11 leap_flag = is_leap_year(year); 12 if(!leap_flag) 13 printf("this year:%d is leap year.",year); 14 else 15 printf("this year:%d is NOT leap year.",year); 16 17 } 18 19 20 int is_leap_year(int year) 21 { 22 if(0 == year%4){ 23 if(year%100 !=0){ 24 return 0; 25 } 26 else if(0 == year%400){ 27 return 0; 28 } 29 return 1; 30 } 31 32 return 1; 33 } 34 35 36 37
/*retry*/ 1 #include<stdio.h> 2 #include<stdlib.h> 3 4 int is_leap_year(int year); 5 int main(int argc, char * argv[]) 6 { 7 8 int leap_flag,year; 9 printf("in put your year:>>>>>>\n"); 10 scanf("%d",&year); 11 leap_flag = is_leap_year(year); 12 if(!leap_flag) 13 printf("this year:%d is leap year.",year); 14 else 15 printf("this year:%d is NOT leap year.",year); 16 17 } 18 19 20 int is_leap_year(int year) 21 { 22 23 if(0 == year % 400){ 24 return 0; 25 } 26 else if(0 == year%4){ 27 if(year%100 !=0){ 28 return 0; 29 } 30 } 31 32 return 1; 33 34 }
1 #include<stdio.h> 2 #include<math.h> 3 4 double myround(double num); 5 6 double myround(double num) 7 { 8 double max,min; 9 max=ceil(num); 10 min=floor(num); 11 printf("max:%lf\n",max); 12 printf("min:%lf\n",min); 13 printf("num:%lf\n",num); 14 if(max - num <= num -min ) 15 return max; 16 else 17 return min; 18 } 19 20 21 int main(int argc,char * argv[]) 22 { 23 24 double num,round_num; 25 printf("In put your number: ====>"); 26 scanf("%lf",&num); 27 28 round_num=myround(num); 29 30 printf("your number is:%.1lf",round_num); 31 }
第二题: #include <stdio.h> #include <math.h> double myround(double x) { if (x>=0) { if (floor(x+0.5)==floor(x)) printf ("%f\n",floor(x)); if (floor(x+0.5)>floor(x)) printf ("%f\n",ceil(x)); } else { if (floor(-x+0.5)==floor(-x)) printf ("%f\n",-floor(-x)); if (floor(-x+0.5)>floor(-x)) printf ("%f\n",-ceil(-x)); } } int main() { double x=-1.1 ,y=4.49, z=-3.51; myround(x); myround(y); myround(z); return 0; }
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